Question

Dosha is creating a new dessert that has two layers shaped like cones. The inner cone is frozen ice cream and has a diameter of 12 cm and a height of 6 cm. The outer layer is a thin wafer shell, like an upside-down ice cream cone, with a height of 15 cm and the same diameter as the inner layer. Dosha will inject a cream filling into the space.

What is the volume of the cream filling?
Use 3.14 to approximate pi and express your final answer in hundredths.


cm3

Answer 1

@FortyTheRapper

Answer 2

I'm trying to grasp if she trying to inject the filling into the outer or inner cone?

Answer 3

Oh, so into the bigger cone?

Answer 4

@FortyTheRapper
I think she's trying to inject it into the outer cone.

So the problem wants you to find the volume of the entire cone, then subtract the volume of the smaller cone (which contains ice cream)

Answer 5

I believe so. :/

Answer 6

I think so.

Answer 7

Either way, Dosha is gonna get diabetes

Answer 8

I agree with Ave then on that logic

Answer 9

Let me think about it. I think I can solve it.

Answer 10

^ Go for it

Answer 11

@FortyTheRapper, do you think you can try? :)

Answer 12

\[V(Outer)-V(Inner) = Filling\]

Both are cones, which are:

\[V = \frac{ 1 }{ 3 }\pi*r^2*h\]

What would the volume of the larger cone be?
What would the volume of the smaller cone be?

Answer 13

Larger is outer and Smaller is inner, btw

Answer 14

Smaller cone: 226.08
Larger cone: 565.2

Answer 15

Looks good!

Now we just subtract the larger cone from the smaller, because we're "cutting" out the smaller cone, if you know what I mean

\[565.2-226.08 =?\]

Answer 16

339.12

Answer 17

yep I would concur. Wow, I was over complicating this problem for sure

Answer 18

Right, so

\[339.12cm^3\] Of Diabetes

Answer 19

Thanks!!!
And lol!!!!!

Answer 20

I have 2 more.

Answer 21

Okay lets see them.