Question

Mitchell poured the contents of a completely filled cone into an empty cylinder, and the cylinder became two-thirds full. The cylinder had a radius of 5 cm and a height of 15 cm.

What were possible dimensions of the cone? Use 3.14 to approximate pi.

A.
h = 5 cm; r = 15 cm

B.
h = 7.5 cm; r = 10 cm

C.
h = 10 cm; r = 7.5 cm

D.
h = 15 cm; r = 5 cm

Answer 1

@FortyTheRapper @raffle_snaffle

Answer 2

hi

Answer 3

Let's first find the volume of the cylinder

That's \[\pi*r^2*h\]

Answer 4

oh this is alot of work we need formulas and stuff

Answer 5

1, 177.5 is the volume of the cylinder.

Answer 6

Right

Since it only filled up 2/3rds of the cylinder though, that means \[(1177.5)(2/3) = V _{cone}\]

Answer 7

Thought so...

Answer 8

@jabez177 hey it's good to double check with someone else. Good job.

Answer 9

785 is the volume of the cone.

Answer 10

Right, so that means

\[\frac{ 1 }{ 3 }*\pi*r^2*h = 785\]

So now it's a matter of getting R and H by itself, like they were x's in an equation

Answer 11

\[\frac{ 1 }{ 3 }*3.14*r^2*h = 785\]

There we go, so numbers on one side, variables on the other

Answer 12

alright

Answer 13

where do we get the radius and stuff from tho?

Answer 14

The answer choices

We isolate to get that r^2 + h = value

We then use those answer choices to plug in and see if it satisfies that value

Answer 15

B.

Answer 16

Perfecto

Answer 17

Thanks! :)