x-8/5=2/4 21/2 9/2 5/2 18
\(\color{#0cbb34}{\text{Originally Posted by}}\) @Mizuki x-8/8=2/4 21/2 9/2 5/2 18 \(\color{#0cbb34}{\text{End of Quote}}\) 8/8 = ?
1
\(\color{#0cbb34}{\text{Originally Posted by}}\) @Mizuki 1 \(\color{#0cbb34}{\text{End of Quote}}\) Okay then. We started from here\[x-\frac{8}{8}=\frac{2}{4}\]Now we get\[x-1=\frac{2}{4}\]
x-1=1/2
Could be \[ \frac{x-8}{8}=\frac 24 \]
\(\color{#0cbb34}{\text{Originally Posted by}}\) @wio Could be \[\frac{x-8}{8}=\frac 24\] \(\color{#0cbb34}{\text{End of Quote}}\) Well. Maybe. @Mizuki is he right?
wrong
LOL. Sorry then @wio o_o
\(\color{#0cbb34}{\text{Originally Posted by}}\) @Mizuki x-1=1/2 \(\color{#0cbb34}{\text{End of Quote}}\) Okay then, moving the 1 over to isolate x\[x=\frac{1}{2}+1\]What does 1 equal in terms of halves?\[1=\frac{?}{2}\]
3/2
\(\color{#0cbb34}{\text{Originally Posted by}}\) @Mizuki 3/2 \(\color{#0cbb34}{\text{End of Quote}}\) Did you add or are you saying 1 = (3/2)?
yea?
\[\frac{?}{2}=1\rightarrow1(2)=?\rightarrow ?=2\]\[1=\frac{2}{2}\]
So then... you add that to 1/2\[x=\frac{2}{2}+\frac{1}{2}\rightarrow x=\frac{3}{2}\text{ OR }1\frac{1}{2}\text{ OR }1.5\]
Is that what you got? @Mizuki
yes
\(\color{#0cbb34}{\text{Originally Posted by}}\) @Mizuki yes \(\color{#0cbb34}{\text{End of Quote}}\) Okay then you've got the answer :D congrats
its not on the multiple choice
yea
Which one? @Mizuki
21/2
It's 1 and 1/2 ??
the question is x-8/5=2/4
You said 8/8 lol
http://prntscr.com/ah4ppj ok here we go. what is the common denominator? that is the common multiple of 5 and 4
20
\(\color{#0cbb34}{\text{Originally Posted by}}\) @Mizuki 20 \(\color{#0cbb34}{\text{End of Quote}}\) Yep! so then\[x-\frac{8}{5}=\frac{2}{4}\]will become this first\[x=\frac{8}{5}+\frac{2}{4}\]Applying the common denominator 20,\[x=4\left(\frac{8}{5}\right)+5\left(\frac{2}{4}\right)\]What did you get?
\[\frac{ 32 }{ 20} +\frac{ 10 }{ 20}= \frac{ 42 }{ 20}\]
\(\color{#0cbb34}{\text{Originally Posted by}}\) @Mizuki \[\frac{ 32 }{ 20} +\frac{ 10 }{ 20}= \frac{ 42 }{ 20}\] \(\color{#0cbb34}{\text{End of Quote}}\) Ok, and that simplifies to? *if this is an answer already then don't simplify it, otherwise it is recommended to
\[\frac{ 21 }{ 10}\]
\(\color{#0cbb34}{\text{Originally Posted by}}\) @Mizuki \[\frac{ 21 }{ 10}\] \(\color{#0cbb34}{\text{End of Quote}}\) Yes good job :D
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