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Mathematics 6 Online
OpenStudy (kanwal32):

differential equation

OpenStudy (kanwal32):

OpenStudy (kanwal32):

@KendrickLamar2014

OpenStudy (kanwal32):

@ganeshie8

OpenStudy (kanwal32):

@confluxepic @Preetha

ganeshie8 (ganeshie8):

maybe start by solving the characteristic equation \[r^2-\sqrt{5}=0\]

OpenStudy (kanwal32):

how

OpenStudy (kanwal32):

i am not getting it

ganeshie8 (ganeshie8):

what exactly are you not getting ?

OpenStudy (kanwal32):

how to substitute r^{2}

ganeshie8 (ganeshie8):

are you asking how i got that equation ?

OpenStudy (kanwal32):

yes

ganeshie8 (ganeshie8):

that is because of euler

ganeshie8 (ganeshie8):

let \(y = e^{rt}\) be a solution of the given differential equation

ganeshie8 (ganeshie8):

\(y = e^{rt}\) \(y'' = ?\)

OpenStudy (kanwal32):

\[e ^{rtn}\]

ganeshie8 (ganeshie8):

Careful, \(y' = \dfrac{dy}{dx}\) \(y'' = \dfrac{d^2y}{dx^2}\)

ganeshie8 (ganeshie8):

\(y'\) is the first derivative of \(y\) \(y''\) is the second derivative of \(y\)

OpenStudy (kanwal32):

ok

OpenStudy (mathmale):

As I see it, you have two choices: Actually solve the D. E. (as you're trying to now), or check out each of the four given answers to determine which satisfies the given D. E. The D. E. is \[y''-\sqrt{5}y=0\] So, supposing we were checking out possible solution #1: 1) Find the 2nd derivative, y'', of that possible solution. 2. Substitute your result for y'' in the D. E. 3. subst. y=possible solution #1 into the D. E. 4. Determine whether or not the D. E. is true after these substitutions have been made.

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