Question

There are four capacitors with capacitances and breakdown voltages mentioned. Two of them are in series (3C,1kV and 2C,2kV) and this is in parallel with two other capacitor in series
(7C,1kV and 3C,2kV) .What should be the maximum value of external emf source such that no capacitor breaks down??

Answer 1

@ganeshie8 pls help

Answer 2

@priyar

Answer 3

@ganeshie8

Answer 4

Q is same on capacitors are in series

Answer 5

Say the voltages across capacitors in given order are V1, V2, V3, V4

Answer 6

Let V be the maximum emf allowed

Answer 7

Then you need to find V such that :

V = V1 + V2
V = V3 + V4
3CV1 = 2CV2
7CV3 = 3CV4
V1 < 1kV
V2 < 2kV
V3 < 1kV
V4 < 2kV

Answer 8

Correct !!

Answer 9

Does that mean that
V=5/3V2
And V=10/3V3??

Answer 10

So potential should be 10/3 ..
Ryt??

Answer 11

Bt that's not the ans!

Answer 12

express each of V1, V2, V3, V4 in terms of V

Answer 13

Or even the opposite of it..
V in terms of each of them..!

Answer 14

And solving this i got V can be at max 10/3..!

Answer 15

is the answer 2.5kV ?

Answer 16

Lemme check!

Answer 17

Yep..

Answer 18

then try again

Answer 19

i have got that answer using your method oly

Answer 20

Okay..

Answer 21

I must see once again then!

Answer 22

V < 5/3V2
V < 2/5V1

V < 10/3V3
V < 10/7V4

Answer 23

Ty!!

Answer 24

Np:)