When studying radioactive material, a nuclear engineer found that over 365 days, 1,000,000 radioactive atoms decayed to 971,984 radioactive atoms, so 28,016 atoms decayed during 365 days. a. Find the mean number of radioactive atoms that decayed in a day. b. Find the probability that on a given day, 50 radioactive atoms decayed.
do you know that mean is
the mean teacher averaged their grades??
so you subtract 971,984 from 1 mil to get the change
then you divide that number by 365
to find the mean
Yes its the second half that frustrates me
idk about the second part
76.756
im not good at probability unless its like a bag of marbles
its called a poisson distribution
Do you know why Poisson distribution should be used here?
i do not, why?
Well, Poisson is used when: 1. Occurrences are all independent 2. We know the average number of occurrences in a time span. 3. We want to know the probability of x occurences
Okay
So are you familiar with this: \[ \Pr(X=x) = \frac{\mu^xe^{-\mu}}{x!} \]
Part one lets you find \(\mu\), and part two tells you to use \(x=50\).
yes i have seen this before! e = 2.71828 i believe!
Anyway, can you plug it in then?
\[ \Pr(X=50) = \frac{\left(\frac{28016}{365}\right)^{50}e^{-28016/365}}{50!} \]
It's going to be a very small number, because getting exactly \(50\) is not a lot
what is e?
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