Question

I have two machines a pulley and a block and tackle
I have 5 weights weighing 1 gram 2 grams 3 grams 4 grams and 5 grams. On each machine I raise the weight 5 cm.
pulley
1 gram = 1 newtons of downward force
2 gram = 2 newtons of downward force
3g = 3n
4g = 4n
5g = 5n
Block and tackle
1g = .5n
2g = 1n
3g = 1.5n
4g = 2n
5g = 2.5n

Answer 1

How did the work output relate to the work input for the pulleys? Explain using your data.

Answer 2

@Michele_Laino @Somy

Answer 3

from the data, I get this:
work done by the pulley, is \(L_P= F \cdot d\)
whereas, work done by the block and tackle, is \(L_{B-T}=(F/2) \cdot d\)
where \(d=5\) cm
so we have this ratio:
\[\frac{{{L_P}}}{{{L_{B - T}}}} = \frac{{F \cdot d}}{{\left( {F/2} \right) \cdot d}} = ...?\]