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Find all polar coordinates of point P where P= -pi/6.
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wait wait
P=(1,-pi/6)
Well, I guess you can just keep adding or subtracting \(2\pi\), so maybe: \[ \forall z\in \mathbb Z\quad \left(1,-\frac \pi6+2\pi z \right) \]
(1, -pi/6 + (2n + 1)π) or (-1, -pi/6 + 2nπ) (1, -pi/6 + 2nπ) or (-1, -pi/6 + 2nπ) (1, -pi/6 + 2nπ) or (1, -pi/6+ (2n + 1)π) (1, -pi/6 + 2nπ) or (-1, -pi/6 + (2n + 1)π)
these are my choices
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is it the second one?
@wio
I think it is the last one
Because it seems: \[ \left(-1,-\frac \pi 6+\pi + 2\pi z\right) \]Are solutions as well, and this simplifies to: \[ \left(-1,-\frac \pi 6+(2 z+1)\pi\right) \]
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