If a sample contains 5.850 x 10^22 formula units (particles) of iron (III) chloride, what is its mass, in grams?
Particles --> mol FeCl3 --> Mass of FeCl3
5.850x10^22 x 1mol FeCl3/6.022x10^23 x 162.2g/1mol FeCl3
is this correct??
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OpenStudy (korosh23):
Please clarify something for me. By formula units (particles), do you mean atoms?
OpenStudy (matt6288):
yeah i think thats what the question means
OpenStudy (matt6288):
Fe = 55.85 Cl= 3 x 35.45
FeCl3=162.2
OpenStudy (matt6288):
to find how many particles are in FeCl3 I would multiply 162.2 by 6.022 x 10^23
OpenStudy (korosh23):
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OpenStudy (matt6288):
what? you divide 5.850x10^22 by 4?
OpenStudy (korosh23):
|dw:1458447908009:dw|
OpenStudy (korosh23):
yes
OpenStudy (korosh23):
If you follow that process. You should get the right answer.
OpenStudy (matt6288):
so you dont even use 6.022 x 10^23
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Yes you use avorgado's number. This means you divide your total particles by that number to get moles. Then moles x molar mass. There you go. You had the right answer. Sorry if I confused you.