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Chemistry 6 Online
OpenStudy (matt6288):

If a sample contains 5.850 x 10^22 formula units (particles) of iron (III) chloride, what is its mass, in grams? Particles --> mol FeCl3 --> Mass of FeCl3 5.850x10^22 x 1mol FeCl3/6.022x10^23 x 162.2g/1mol FeCl3 is this correct??

OpenStudy (korosh23):

Please clarify something for me. By formula units (particles), do you mean atoms?

OpenStudy (matt6288):

yeah i think thats what the question means

OpenStudy (matt6288):

Fe = 55.85 Cl= 3 x 35.45 FeCl3=162.2

OpenStudy (matt6288):

to find how many particles are in FeCl3 I would multiply 162.2 by 6.022 x 10^23

OpenStudy (korosh23):

|dw:1458447846494:dw|

OpenStudy (matt6288):

what? you divide 5.850x10^22 by 4?

OpenStudy (korosh23):

|dw:1458447908009:dw|

OpenStudy (korosh23):

yes

OpenStudy (korosh23):

If you follow that process. You should get the right answer.

OpenStudy (matt6288):

so you dont even use 6.022 x 10^23

OpenStudy (korosh23):

Yes you use avorgado's number. This means you divide your total particles by that number to get moles. Then moles x molar mass. There you go. You had the right answer. Sorry if I confused you.

OpenStudy (korosh23):

|dw:1458448230901:dw|

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