Question

What can you say about this molecule from reading its IR and NMR?

Answer 1

For sure this molecule has an aldehyde due to the c-h stretch and the carbonyl at 1601.2 cm^-1 in the IR and the chemical shift in 10 ppm with a narrow singlet.

Answer 2

What else can you include?

Answer 3

@Kainui @Photon336

Answer 4

in IR you can pretty much ignore the fingerprint region anything under 1,000

Answer 5

Correct.

Answer 6

just think of that region as background let me pull up the IR chart

Answer 7

Alright.

Answer 8

For the IR these are all the stretches I found

cm^-1

2982
2739
3361
2539
1910
1682
1601

Answer 9

You don't by chance have the empirical formula for your compound do you?

Answer 10

No.

Answer 11

@zela101

I think I saw two bands 1600,1500 probably some kind of aromatic system on the IR
when looking at the NMR, there are some aromatic protons there too which confirms that we have an aromatic system, between 6-8 ppm

Answer 12

Yes, i suspected the aromatic existing because when i did a DNPH, it had a precipitate very bright red which indicates the existing of aromaticity (based on what i read on my book).

Answer 13

also another thing

Answer 14

My unknown looks like this

Answer 15

there is no OH in this compound I can bet you on that.

usually an OH is a broad stretch

Answer 16

Yes, definitely no -OH group. There is no sight of a broad peak existing around the 3000 cm^-1

Answer 17

I suspect a C=C-H stretch at 3361.4. Do you see it?

Answer 18

\(\color{blue}{\text{Originally Posted by}}\) @Photon336
For the IR these are all the stretches I found

cm^-1

2982
2739

3361-> this could be aromatic protons C-H
2539

1682--> C=C aromatic system ,
1601---> C=C aromatic system
\(\color{blue}{\text{End of Quote}}\)