Fan & Medal
A total of 25.0 mL of 0.150 M potassium hydroxide (KOH) was required to neutralize 15.0 mL of sulfuric acid (H2SO4) of unknown concentration.
How do i find the solution, molar ratio, volume, and concentration of the base known?

Question

Fan & Medal
A total of 25.0 mL of 0.150 M potassium hydroxide (KOH) was required to neutralize 15.0 mL of sulfuric acid (H2SO4) of unknown concentration. 
How do i find the solution, molar ratio, volume, and concentration of the base known?

priyar · Answer

first equate the gram equivalents

pagen13 · Answer

how?

priyar · Answer

gram eqts = no. of moles * n-factor
 haven't you learnt this at school?

pagen13 · Answer

my teacher hasn't taught me any of this. she gives my assignment and no help.

priyar · Answer

oh..ok wait i will send you a good link to learn from.

pagen13 · Answer

Okay!

priyar · Answer

http://environmentalchemistry.com/yogi/chemistry/MolarityMolalityNormality.html

priyar · Answer

this talks about molarity,molality and normality..
gram equivalents is normality*volume

priyar · Answer

hope it helps!

priyar · Answer

after reading from that link you may wanna solve this practice problem.. just to get a clear picture .. https://www.youtube.com/watch?v=IwLes-49xVs

pagen13 · Answer

I am still confused..

photon336 · Answer

$$H_{2}SO_{4} + KOH \rightarrow K_{2}SO_{4} + H_{2}O$$

$$N_{a}V_{A} = N_{b}V_{B}$$

Na = molarity of acid ? 
Va = volume of acid 

Nb = molarity of base  
Vb = volume of base   

you can easily find the molarity of sulfuric acid 

when you neutralize something the number of moles of acid and base are equal. 

when you look at the reaction above the molar ratio of acid to base is 1:1 

we can easily re-arrange the formula to find the molarity of acid.

$$\frac{ N_{b}V_{b} }{ V_{a} } = molarity~acid $$