Mathematics
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OpenStudy (samigupta8):
The condition that the parabolas y^2=4c(x-d) and y^2=4ax have a common normal other than x axis (a>0,c>0 and c>a) is
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OpenStudy (samigupta8):
@ganeshie8
OpenStudy (samigupta8):
I found this
a/m=-md+c/m
OpenStudy (samigupta8):
@phi
OpenStudy (phi):
what's a "common normal" ?
OpenStudy (samigupta8):
The normal that is common to both the curves!
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OpenStudy (samigupta8):
Options are
A).2a<2c+d
B).2c<2a+d
C).2d<2a+c
D).2d<2c+a
OpenStudy (phi):
yes, but what is the definition of a normal ?
OpenStudy (samigupta8):
A line that is perpendicular to tangent.
OpenStudy (samigupta8):
@ikram002p
OpenStudy (samigupta8):
@pawanyadav
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OpenStudy (pawanyadav):
Suppose a point (x,y)
Find dy/dx for both curve then equate it..
OpenStudy (samigupta8):
Did u see my equation in the second post ??
OpenStudy (pawanyadav):
What is m there ?
OpenStudy (pawanyadav):
slope of tangent or normal
OpenStudy (samigupta8):
Wait!! I did wrong..
I equated the equations of common tangent to the curves
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OpenStudy (samigupta8):
I got this now
2am+am^3=2cm+cm^3+md
OpenStudy (pawanyadav):
So you got option A
OpenStudy (samigupta8):
Oops A only!
OpenStudy (samigupta8):
Ty
OpenStudy (pawanyadav):
Yes. ..
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OpenStudy (samigupta8):
No ...it should be 2a>2c+d
OpenStudy (samigupta8):
@pawanyadav
OpenStudy (pawanyadav):
Why..
OpenStudy (samigupta8):
I got this
2a+am^2=2c+cm^2+d
And if we take the terms to left side we get
2a-2c-d=(c-a)m^2
So 2a>2c+d
OpenStudy (pawanyadav):
Yes , sorry ... I'm just confused in my question... You are right
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OpenStudy (samigupta8):
Okk..np
OpenStudy (pawanyadav):
I'll tag you in my question .if you can help
OpenStudy (samigupta8):
I replied lol..