Ask your own question, for FREE!
Mathematics 16 Online
OpenStudy (ccastudentgrade10):

HELP PLEASE FAN/MEDAL im three weeks behind and im stuck on these type of questions Calculate the [H^+] for the aqueous solution in which [OH^-] is 1 x10^-3. Is this solution acidic, basic or neutral? Show your work

OpenStudy (ccastudentgrade10):

@dayakar ?? sry idk if u helped me w chem or math before

OpenStudy (anthony1914):

Because [H+][OH-]= Kw = 1.0 x 10^-14 [H+]= Kw/ [OH-]= 1.0x 10^-14 / 1 x 10^-11 =1 x 10^-3 mol/L pH = - log [H+]= - log 1 x 10^-3 = 3 < 7 the solution is acidic

OpenStudy (ccastudentgrade10):

OHHHHHHHHH @anthony1914 that makes so much sense could you help me with one more?

OpenStudy (anthony1914):

sure

OpenStudy (anthony1914):

what grade are you in

OpenStudy (ccastudentgrade10):

10

OpenStudy (ccastudentgrade10):

lassify each solution as either an acid or a base using the properties that are stated. What are two ways these solutions are similar? Solution A – has a bitter taste and feels slippery. Solution B – has a sour taste and feels sticky.

OpenStudy (ccastudentgrade10):

I think a is a base and b is an acid bc of the taste, but idk what the feel has to do w anything?

OpenStudy (ccastudentgrade10):

also LASTONE I PROMISE can you check my answer? 5. (1 point) What mass of Na2SO4 is needed to make 1.5 L of 3.0 M solution? (Na = 23 g; S = 32 g; O = 16 g) * Numbers in chemical formulas are subscripts unless there is a ^ to make it superscript • 142 g -->• 213 g • 639 g • 1,280 g

OpenStudy (anthony1914):

solution a is a base

OpenStudy (anthony1914):

so b is a acid

OpenStudy (ccastudentgrade10):

okay, thank you! is 5 right?

OpenStudy (anthony1914):

no i dont think so 1 sec

OpenStudy (anthony1914):

i belive you were right

OpenStudy (ccastudentgrade10):

okay thank you!!

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!