Question

Graph the first six terms of a sequence where a1 = 4 and r = 2

Answer 1

@Atsie @Qwertty123 @dumbcow

Answer 2

this is a geometric sequence
a1 , a1*r, a1*r^2, a1*r^3 .... a1*r^5

Answer 3

so first 2 terms are
4 , 4*2

Answer 4

4*2= 8
So what next?
Do I just plug in 4 to all the equations you gave me?
@welshfella

Answer 5

yes the next term is 4 * 2^2

Answer 6

then 4 * 2^3
do you see the pattern?

Answer 7

Next would be 4*2^2= 16

Answer 8

right

Answer 9

So I think the answer would be the graph with points
(1,8) (2,16) (3,32) (4,64) (5,128) (6, 256) right?

Answer 10

Or am I wrong?... I'm not so sure anymore but I THINK ^^ those points are right

Answer 11

yes - sorry i mad a mistake - you multiply by 2 not by 4

Your results are correct

Answer 12

Thank you!! :)

Answer 13

yw

Answer 14

Can you help me with one more?

Answer 15

I have 5 minutes only bu t ok

Answer 16

Thanks
Calculate the average rate of change for the graphed sequence from n = 2 to n = 4.

Answer 17

And the points on the graph are (1,-3) (2,-3.5) (3,-6.75) (4,-10.25) (5,-15.1875) (6,-22.78125)

Answer 18

average rate of change = 4th term - 2d term
-----------------
4 - 2

= 64 - 16
------ = 48 / 2
4 - 2

Answer 19

gotta go

Answer 20

@Qwertty123
@Atsie

Answer 21

@dinamix

Answer 22

@phi

Answer 23

@dinamix and @phi
I need help on my second question, not my first one

Answer 24

can you make it a new post. It's tough to follow this.

Answer 25

Ok, I will :)