Question

64^2x-3=1/32^5. solve for x...please help

Answer 1

\[64^{2x-3}= \frac{ 1 }{ 32^{5} }\]

Answer 2

what have you tried?

Answer 3

i used 2 so that i could have the same base but its not workinh

Answer 4

2 is the correct base :)
64 = 2^6
32 = 2^5

Also we will need
\(\dfrac{1}{x^n} = x^{-n}\)

it would be helpful if you show your work :)

Answer 5

i think im more stuck on how to write the actual problem

Answer 6

6(2x-3)=?

Answer 7

\(64 =2^6 \\ \Large 64^{2x-3} = (2^6)^{2x-3} = 2^{6(2x-3)}\)

Answer 8

\(\dfrac{1}{32^5 } = 32^{-5} = (2^5)^{-5} = 2^{5\times(-5)}= ...\)

Answer 9

so, comparing the exponents
6(2x-3) = 5*(-5)

Answer 10

thank you

Answer 11

welcome ^_^

Answer 12

let me know if you have any more doubts in this problem :)

Answer 13

i got -13/7 is that what you got too?

Answer 14

@hartnn

Answer 15

12x-18 = -25
12x = 18-25
12x = -7

x = -7/12

how did you get -13/7 ?

Answer 16

at first i got 19/4 then i got -13/7

Answer 17

if you show your work, i can help you to spot the error :)

Answer 18

ok i see what i did wrong.thanks you again
=)

Answer 19

welcome ^_^