I am for real Struggling On my Stoiciometry and need help like now!!

Question

wilsondanielle · Answer

what's the question?

anonymous · Answer

|dw:1458603445252:dw|

anonymous · Answer

It says for the first part. Balance the equation

wilsondanielle · Answer

General procedure : 
1- Balance metals
2- Balance non-metals, NOT including O or H
3 - Balance O
4- Balance H

Try following those steps for the first part

anonymous · Answer

The second Part it says what mass of H2SO4 reacts with sodium hydroxide, what mass of water is produced?

wilsondanielle · Answer

eg : you have 2 Na on the LHS, but only one one the right, so you need to put a coefficient of 2 in front of the NaOH term

wilsondanielle · Answer

Let's start by balancing and then we'll move to the second part

anonymous · Answer

Okay... So 2H2SO4+2NOH

anonymous · Answer

Is that right? would you just simply put two on one side if it is two on the other?

wilsondanielle · Answer

Not necessarily. You don't need to add across the entire side. 

At the end of step 1, you have 

H2SO4 + 2NaOH = Na2SO4 + H2O

If you add 2 in front of the H2SO4 reagent, you end up with 2S on the RHS and only one on the left so that doesn't help - Sulfur (nonmetal) is already balanced, meaning you can move on to step 3 - oxygen. Count how many oxygens you have on either side and see if they match.

anonymous · Answer

Okay I see

wilsondanielle · Answer

You can also make a little table to help you keep track. Right now you have 
               RHS                    LHS
Na              2                       2
S                1                        1
O                6                       5
H                4                       2

anonymous · Answer

ok

wilsondanielle · Answer

So how would you balance the oxygens? You're missing one on the LHS - which product should you add a coefficient to? How does that change the table?