come up with an expression equivalent to 1-tan^4(x)
the answer would look similar to sec-sec or something like that. All I know is that sec is in the answer
See.. first start with using the identity: \(a^2 - b^2 = (a-b)(a+b)\)
so (1-tan^2)(1+tan^2) ???
Great!!
Now what is 1+ tan^2 ?
sec^2x
Good!
Anything you can think about our second buddy... 1 - tan^2 x ?
? would I have to separate that?
(1-tanx)(1+tanx) ???
I think just leave that 1-tan^2 x
oh.
You wanted a sec^2 right? You got that already :)
I have it. but the answer choices have sec on both sides
answer choices r faded so its hard to see
Ohh well that's a tough task then...
like one is 2sec^2x-sec^4x......or -2sec^2x-sec^4x
thats 2 answer choices right there
hmm... well let's see what we have till now... \(1-\tan^4 x\) \(=(1-\tan^2 x)(\sec^2x)\)
There are several things we can do for 1 - tan^2 Like we have.. \[\cos(2x) = \frac{1- \tan^2 x}{1+\tan^2 x}\]
So, if I replace 1- tan^2 x with cos(2x) (sec^2x)
for example.... Which of the following expressions is equal to 1-sec^4x???? A. -2tan^2x-tan^4x C. 2tan^2x-tan^4x B. tan^2x-tan^4x D. -2tan^2x+tan^4x The answer was A..... So for the problem we were doing I thought it would be similar.
I don't think there is any use of simplifying it any further... let's just go with cos(2x)*sec^4 x
Same here, but its not any one of the answer choices.
But I appreciate your help!
Your welcome :)
So what are your choices?
Btw you can write 1-tan²x as 2 - sec²x
Very hard to see as i did get a faded print out but from what I can manage to make out I have A.2sec^4x+sec^4x B. sec^2x-sec^4x C. 2sec^2x-sec^4x D. -2sec^2x-sec^4x
yeah so C is correct
so my answer would be positive?
(2-sec²x)sec²x 2sec²x-sec^4x
ohhhh
thanks a lot
Join our real-time social learning platform and learn together with your friends!