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Suppose a variable X is normally distributed with a standard deviation of 10. Given that 30.85% of the values of X are greater than 70, what is the mean of X?
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so Z=(70-mu)/10, and P(X>Z)=30.85%, solve for mu?
any illustrations ?
nope, thatsall of the question from our textbook
k
ok, so (70-mu)/10=invNorm(30.85%)
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sorry, invnorm(1-.3085)
k, so here is a standard deviation formula |dw:1458664047075:dw|
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