Question

Please help. Find the volume of the following figure. Leave square root in answer. Picture in comments

Answer 1

Is that a square pyramid?

Answer 2

It is a trianglular pyramid

Answer 3

*triangular

Answer 4

Seems that the volume would be
\[\frac{ 1 }{ 3 }(b)(h)\] in that case

You can find h by simply taking the height, and you can find base by finding the area of the base triangle, so:

\[V = \frac{ 1 }{ 3}(area-of-base - \triangle)(height - of- pyrimad)\]

Do you know the area of the base of the height?

Answer 5

That looks good to me. So you have

\[V = \frac{ 1 }{ 3 }(2\sqrt{12})(4)\]
Also known as:

\[V=\frac{ (2\sqrt{12} )(4)}{ 3}\]

Answer 6

okay so it is 8 sqrt12/3
How can I get the sqrt out of the fraction?

Answer 7

\[V = \frac{ 8\sqrt{12} }{ 3 }\]
I'm not understanding what you mean. Like, get rid of the denominator or...?

Answer 8

The answer has to have a fraction multiplied by the sqrt

Answer 9

Ah, we could multiply by 1/3, since 1/3 times 3 = 1

\[\frac{ 1 }{ 3 }*8\sqrt{12}\] if thats what you meant

Answer 10

So it would be 8/3 * sqrt12?

Answer 11

\[\frac{ 1 }{ 3 }*16\sqrt{3}\] if you wanted to maximize your radical simplifying.

And \[\frac{ 8 }{ 3 }* \sqrt{12} \] is a different value from \[\frac{ 1 }{ 3 }*8\sqrt{12}\]

Answer 12

Or not, nvm

Answer 13

okay, thanks for your help

Answer 14

You're welcome. You did great