Question

dilute 10.0 mL of the 0.50 M NaCl by adding distilled water until 100 mL of solution are produced.

Does the 100 mL of diluted NaCl have more, less, or the same quantity of NaCl as the original 10.0 mL of 0.50 M NaCl?

Answer 1

@SLP-HUERTA
@Photon336
@Cuanchi

Answer 2

would the answer be that they have the same and if yes why?

Answer 3

@Tennis5518

Answer 4

haha

Answer 5

Any clues?

Answer 6

C1 = original concentration
V1 = original volume
C2 = final concentration
V2 = final volume


C1 x V1 = C2 x V2

C2 = (C1 x V1)/C2

C2 = (0.5 x 10)/100

C2 = 0.05

Answer 7

@Photon336

Answer 8

So we're diluting 10.0 mL of the 0.50 M NaCl by adding distilled water until 100 mL of the solution is produced.

well, I guess we can figure out the new concentration.


\[N_{a}V_{a} = N_{b}V_{B}\]

Answer 9

Na = 0.50M
Va = 10mL

Nb = ?
Vb = 100mL

Answer 10

It has the same quantity. You are not adding NaCl, and it doesn't just vanish.

All that changes is the concentration of NaCl (the amount per unit volume), but the amount is constant.

Answer 11

\(\color{#0cbb34}{\text{Originally Posted by}}\) @Tennis5518
C1 = original concentration
V1 = original volume
C2 = final concentration
V2 = final volume


C1 x V1 = C2 x V2

C2 = (C1 x V1)/C2

C2 = (0.5 x 10)/100

C2 = 0.05
\(\color{#0cbb34}{\text{End of Quote}}\)
It true

Answer 12

\[\frac{ NaVa }{ Vb } = Nb \]
\[\frac{ 0.50M*0.01\cancel\L }{ 0.1\cancel\L } = 0.05M\]

Answer 13

yeah I agree with @Tennis5518 like you have the same amount of NaCl it's just that it's concentration is not as much.

Answer 14

ok thanks so much for your help :)

Answer 15

Np :)