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Mathematics 19 Online
OpenStudy (studygurl14):

@jigglypuff314 @michele_laino @pooja195 @johnweldon1993 @irishboy123

OpenStudy (studygurl14):

OpenStudy (studygurl14):

Can you take a screenshot? the link is blocked for me

OpenStudy (stamp):

I'll see what I can do. but before that, do we know what the answer should be?

OpenStudy (studygurl14):

no

OpenStudy (stamp):

Ok well to find the volume, we'll need to integrate the area of the triangles. Let's see if we can establish A(y) for each triangle

OpenStudy (studygurl14):

i'm assuming these are the cross-sections of a cone, right?

OpenStudy (studygurl14):

a slanted cone

OpenStudy (stamp):

Ok so it's an iscocleses triangle meaning the base and the height are the same. the base leg is equal to 2x, and the height is also going to be equal to 2x. meaning the area of our triangles are \[\ A(x)=\frac{1}{2}(2x)(2x)=\frac{1}{2}(2x)^2\]

OpenStudy (studygurl14):

ah, okay. And then I integrate that?

OpenStudy (stamp):

\[A(x)=2(x)^2\] solve x^2+y^2=1 for x, replace x with the equation solved for y, and integrate taht from -1 to 1

OpenStudy (stamp):

solving x^2+y^2=1 for x gives \[x=\sqrt{1-y^2}\] and when we substitute into \[A(x)=2(x)^2\]we get \[A(y)=2(1-y^2)\]

OpenStudy (studygurl14):

why?

OpenStudy (stamp):

why do we want it in terms of y? well the initial problem gives us y from -1 to 1 so it makes sense to integrate it with respect to y from -1 to 1

OpenStudy (studygurl14):

oh, i see

OpenStudy (studygurl14):

do we need pi at all?

OpenStudy (stamp):

so we want to \[\int A(y) dy \] from -1 to 1

OpenStudy (stamp):

no pi

OpenStudy (studygurl14):

k, so |dw:1458688800492:dw|

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