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OpenStudy (anonymous):
A piston has an external pressure of 6.00 atm. How much work has been done in joules if the cylinder goes from a volume of 0.150 liters to 0.490 liters?
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OpenStudy (anonymous):
@V1r3z
OpenStudy (anonymous):
For this we can use the equation \[work (W) = P(Pressure)\Delta V(Volume)\] Since we know that the pressure is constant, and we have the initial and final volume, calculating work done is a breeze. We just plug the numbers we are given in for the variables. W = 6.00atm(0.490L-0.150L) = 2.04 J of work done.
OpenStudy (anonymous):
It keeps telling me that its in units of atmosphere and to convert it to joules.
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