Help, will medal!
You gotta use trignometry here.Are you familiar with the trig ratios or do you want me to do it for ya?
I'm going to need some assistance =)
Okay,how do you think we will do it @AnonymousKiddz?
Help? Lol
Well let's see if you guys end up with the same answer, or figure out something, I just need some help
@bournville you were pretty confident too darling ;)
It is geometry but advanced, I need help though :/
Okay,so we use the Tan ratio here We know that tan=opposite/adjacent We will use the tan of 60 degrees here The opposite side here will be 8 and the adjacent will be x The value of tan60 degrees is square root of 3 can you do it now?
So square root of 60= 8/x
Well I need @bournville to confirm my answer =)
Okay,so what is your answer?
@bournville is correct, trig must be used to find that length of the triangle. SOH CAH TOH is what you can use to find the missing length. Appropriate label your triangle, and you will be able to determine which trigonometric function to use. NOTE: You are looking for the smallest triangle leg, at least not the hypotenuse. You're answer should technically be smaller than 8, but do not always assume so because most are not drawn to scale unless otherwise noted.
Oh I had a typo. It should be TOA.
Are you sure you should use tan though?
Is it not TAN?
I am sure it will be tan Do you have h? No,so you gotta find some relation between opposite and adjacent
But you're finding 'x', not 'h'.
Lets use tan in this example, real quick.
Yeah,so we don't need h
How do ya think we wud do it @Maddy1251 ?
tan(60) x 8 = 13.86. I really doubt the smaller leg is almost double the second largest leg. This could possibly be h! :)
@zarkam21 it won't be square root of 60.It would be square root of 3
It's been many years since I have done just the simple trig.. I would try probably cos or sin. I mean you could always try the two, and if you are really willing ; a^2+b^2=c^2 to check
Personally my gut is saying cos.
1.73?
yeah
So the overall answer is ...?
1.73 isn't an answer.
it is the value of root3
Use 1.73 in the equation
yep
I think you should use cos(60) x 8 = 4. sin(60) x 8 = 6.93 However that isn't an answer choice when using sin.. you be the judge. I wouldn't use tan.
Equation is ?
https://www.mathsisfun.com/sine-cosine-tangent.html This may help. I gotta go. :)
Idk man, I just came here for help and now I'm even more confused
@jhonyy9 please see if this correct
there's more than one way in which to skin a cat, and more than one way in which to solve this problem. Use of trig is the key. You know all three angles in the given triangle: 30, 60 and 90 degrees, so it's a right triangle. Which trig function (or functions) would best suit for finding the length of side x, and why?
@mathmale will definitely help.
@zarkam21 Could you please type out the definitions of the sine, cosine and tangent functions? Example: cos theta = (adjacent side) / (hypotenuse)
Well I know the 8 will be helpful
Yes hold on, I will type them up
1.73=8/x This is your equation
That side length 8 is essential to solving this problem. Please give zarkam21 time to respond.
I am sorry @mathmale
Sin= Opposite/Hypotenuse Cos= Adjacent/Hypotenuse Tan= Opposite/Adjacent
Great. Next, decide which angle you'd like to work with (your choice here doesn't matter).
Let's try sin =)
No, please decide whether you're going to include the 30 degrees angle in your calculations or the 60 degree angle. Which?
Oh okay, 30
fine, good. Now, focusing on that 30 degree angle, is 8 the "adjacent side" or the "opposite side"?
Adjacent Side
Here, "adjacent" means "next to." Yes, you're right. And what is the name of the side whose length you want to find (x)?
It's called the " side."
...with reference to the 30 degree angle.
Missing?
It's missing, yes. It's represented by "x," yes. This side is part of the triangle. It's not the hypotenuse, not the adjacent side. So, it must be the " " side.
Umm idk angle,leg
opposite side. x is opposite the angle 30 degrees, correct?
Yes yes that is correct
So, which of the trig functions you've identified includes the opp side, the adj. side and the 30 deg. angle?
Tan?
Yes. write out tan 30 = opp / adj, and then write it again with the correct numerical value of the adj. side. tan 30 deg = ( ) / ( )
Tan= x/30
I mean x/8
but you haven't written in the value of the adjacent side (which you correctly identified earlier). Also, 30 is the angle, and so that 30 must go with the tangent function: tan 30 deg = ( ) / ( ) Try again.
Mathmale ?
tan 30 deg = (opp side) / ( 8 ) since the adj side is 8
Isn't the opposite x and adjacent 8
reprsent "opp side" by x. Yes, to answer your question, yes.
Mathmale ?
Therefore, \[\tan 30 =\frac{ ? }{ 8 }\]
so x/8
Can u help me mathmale when u done
Yes, tan 30 deg = x/8
How would you solve that for x? You'll need to find the value of tan 30 deg.
Wouldn't you do the opposite and multiply
Certainly you could mult. both sides of the eq'n by 8 to eliminate the fraction. That would give you 8 tan 30 = x. But you'll still have to find the tangent of 30 deg. tan 30 = 1/sqrt(3). Can you verify that this is correct?
Therefore, \[x=8(\frac{ 1 }{ \sqrt{3} })=?\]
Strictly speaking, you need not find tan 30 as a decimal fraction unless told to do so. Think of "tan 30 = 1 / sqrt(3)" and leave the right side as is.
@zarkam21 : Need closure to this post. Where are you? Any questions?
I am here
I put this in my calculator and got 0.072
0.072 for what? I was suggesting that you leave your answer in the form x=8(1/sqrt(3), or x=8/sqrt(3).
OKay but is that one of the choices?
I don't have the answer choices here. So you tell me. x could be written in several forms, including \[8/\sqrt{3}\]
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