Can someone please help me? I really need help... I will fan and Medal Question~ Simplify the following exponential expressions. 5x^6y^4 --------- -20xy^-2z
@phi would you mind helping me?
let's hope OS behaves. meanwhile, what is 5/-20 ? (remember this is plus divided by minus, so the answer is going to be negative)
-1/4
0?
oh! I meant anything divided by itself is 1!
oh okay, haha that's what I thought it was supposed to be! ok so x/x=1
all of these problems use that idea (but there are short-cuts) if you see \[ \frac{x}{x}\] that is 1 if you see \[ \frac{x\cdot x \cdot x}{x} \] that is the same as \[ \frac{x}{x} \cdot x\cdot x \] and x/x is 1, so you get \[ 1\cdot x \cdot x\] and we can ignore multiply by 1 (it does not "do anything") in other words you get \[ x \cdot x\] does that make sense?
you have in your problem \[ \frac{x^6}{x} \] the "little 6" means x times itself 6 times so (if we wanted) we could write this as \[ \frac{x \cdot x \cdot x \cdot x \cdot x \cdot x}{x}\] and the x in the bottom will "cancel out" one of the x's up top that will leave only 5 x's up top we would write that in "short-hand" as \[ x^5\]
next we do the y's \[ \frac{y^4}{y^{-2}} \] the bottom y is y^-2 the negative number -2 is a bit tricky. You have to learn this rule: if you move a number or letter from bottom to top, you change the sign of the exponent in other words, to make that -2 turn into a +2, we "move" the y^-2 up top \[ \frac{y^4 y^2}{1} \] that is 4 y's multiplied together times 2 more y's so y*y*y*y * y*y how many y's is that altogether ?
y=6
yes, but not y=6 you have y*y*y*y*y*y and if you don't like to write that out, just write y and put an ^ and a 6 next to it y^6 (or if you use the equation editor, or write it) make the 6 small in the upper right. \[ y^6\]
do you understand how the "short-cut" way to write it works ?
yes sir
do you know how to write x*x*x*x using the short way ?
x^4?
yes. and do you know how to write y^3 the "long way" ?
y*y*y do you mean this way?
yes. you are doing good. now can you simplify \[ \frac{x\cdot x\cdot x}{x\cdot x\cdot x} \] notice you can "cancel" each "pair of x" (one in the top with one in the bottom)
yes sir
what does it simplify to ?
@phi it equals 0?
\[ \frac{x\cdot x\cdot x}{x\cdot x\cdot x} \\= \frac{x}{x}\cdot\frac{x}{x}\cdot\frac{x}{x} \\ = 1\cdot 1\cdot 1\\=1 \]
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