Question

calculate the poh of an aqueous solution of .014M NaOH at 25oC

Answer 1

@TheSmartOne

Answer 2

@Cuanchi

Answer 3

NaOH is a strong base so all you need to do is \[pOH=-\log[Base]\] Please note that this does NOT apply to weak bases, only strong bases. For weak bases there are a few extra steps involved. Anyways, just take the -log of the concentration of NaOH to find the pOH

Answer 4

I got 1.85

Answer 5

@nmagnuson Is that what you get?