Question

Log question please help?

Answer 1

Solve:
\[\log_43+\log_4(1-x)=\log_4(1+x)\]

Answer 2

I believe my first step would be to cancel out one of the log_4

Answer 3

\[\log_43(1-x)=(1+x)\]

Answer 4

no first you need to get the right side as single log
are you familiar with log properties ?

Answer 5

\[\log_{a} b+\log_{a} c=\log_{a} bc\]

Answer 6

okay soo \[\log_4(1-x)(1+x)\]

Answer 7

log_4(1-x)(1+x)(3)

Answer 8

\[\log_{4} 3\left( 1-x \right)=\log_{4} \left( 1+x \right)\]

Answer 9

oh that's right...

Answer 10

\[\large\rm \log_b x + \log_b y= \log_b (xy)\]
i believe you already applied this rule
now you can cancel out the log
\[\large \rm \log_43(1-x)= log_{4}(1+x)\]

Answer 11

so then I get \[3(1-x)=(1+x)\]

Answer 12

looks good solve for x

Answer 13

\[3-3x=1+x\]
\[2=4x\]
\[x=1/2\]

Answer 14

looks good. good job

Answer 15

yay, thank you so much!