Question

please check

Answer 1

@narissa you made some mistake... how did you solve it ?

Answer 2

e\[4a^2+-a^2=3^2 ~~~~ b+b=2b =3^2b-2b\]

Answer 3

umm looks like you have done some mistakes.. so let's start from beginning?

The question is:

\[(4a^2 + b) - (a^2 + b)\] right?

Answer 4

yes

Answer 5

Great!

So, first we remove the brackets... for the first brackets.. i.e. \((4a^2 + b)\) there is no sign in front of the brackets that means there is a positive sign '+' so that's not going to affect the signs of \(4a^2\) or \(b\)..

So,

\((4a^2 + b) - (a^2 + b) = 4a^2 + b - (a^2 + b)\)

Answer 6

Any problem in this?

Answer 7

ok

Answer 8

we multiply by -1?

Answer 9

Great! Now, we remove the brackets from the second term.. but this time we have a negative sign '-' in front of brackets so we multiply every term inside the bracket with -1

Answer 10

-1 x -1= 1 -1x1=-1

Answer 11

Great!

Answer 12

So, our question will become...

\(4a^2 + b -(a^2 + b) = 4a^2 +b - a^2 - b\)

Answer 13

Any doubt?

Answer 14

no

Answer 15

Nice :) So, we have:

\(4a^2 + b - a^2 -b \)

I bring \(a^2\) terms close to each other and \(b\) terms close...

So,

\(4a^2 -a^2 + b - b\)

Answer 16

4-1=3 1-1=1

Answer 17

Naah.. 1 - 1 is 0..

Answer 18

oh yea duhhh

Answer 19

So, we get:

\(4a^2 - a^2 + b - b = 3a^2\)

Answer 20

3a^2 is my answer thanks !!

Answer 21

:D Great job! :)