Question

Help !

Answer 1

@ganeshie8 @phi @Kainui

Answer 2

we could make an "educated guess" that the answer is related to the area of the upper half of the sphere. otherwise, I assume it's a calculus problem ?

Answer 3

what's next ?

Answer 4

@phi

Answer 5

@MasterLord What formulas do you know of that relate pressure with height

Answer 6

\[\large \bf P=\rho g h\]

Answer 7

@Kainui

Answer 8

@phi

Answer 9

@mathmale @freckles @agent0smith

Answer 10

@zepdrix @MrNood

Answer 11

are you supposed to use integration for this problem ?

Answer 12

i don't think so !

Answer 13

as I posted up above, all the answers have the same structure , with a different multiplier out front. I would guess the multiplier is the area of half of a sphere.

But to derive the answer... that is more difficult. Off-hand, I would have to research it (which I don't have the time to do)

Answer 14

okay !

Answer 15

I can only see that this could be done using calculus (although th eanswers don't look like they have been found that way)

this is not a solution but the beginning of how I would approach it - I'm not sure it will get us there...

The pressure at any given depth of fluid is rho gh

BUT the hemispere is at a range of depths so to get the FORCE you have to get the horizontal projected area and integrat from 0 to pi/2

Answer 16

why not 0 to pi ?

Answer 17

@imqwerty

Answer 18

@Kainui

Answer 19

@ganeshie8

Answer 20

@Miracrown