Question

easy medal

Answer 1

what is the question?

Answer 2

\[4(3x-2)^.33333333334=12\]

Answer 3

solve

Answer 4

\[4(3x-2)^\frac{ 1 }{ 3 }=12\]

Answer 5

there u go

Answer 6

@ganeshie8 @Wendy.Ivette11714 @WhatTehHeck @wherearemytacos @wormynut @Abhisar @AmTran_Bus @baru @carolina4567

Answer 7

(3x-1)^(1/3)=3

Answer 8

-2

Answer 9

i know the awnser but i want to c if im correct

Answer 10

ok. whats the ans

Answer 11

the second one is x=29/39 or x=0.744

Answer 12

no its 9.6

Answer 13

$4\left(3x-2\right)=12$4(3x−2)=12



Show Steps
$\mathrm{Expand\:}4\left(3x-2\right):\quad12x-8$Expand 4(3x−2): 12x−8

$12x-8=12$12x−8=12



$\mathrm{Add\:}8\mathrm{\:to\:both\:sides}$Add 8 to both sides

$12x-8+8=12+8$12x−8+8=12+8


$12x=20$12x=20



$\mathrm{Divide\:both\:sides\:by\:}12$Divide both sides by 12

$\frac{12x}{12}=\frac{20}{12}$12x12 =2012

$x=\frac{5}{3}$x=5/3

Answer 14

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Answer 15

\[x=\frac{(12/4)^3+2}{3}=29/3\]

Answer 16

no its not to the third

Answer 17

its to the \[\frac{ 1 }{ 3 }\]

Answer 18

FULL STEP
\[4(3x-2)^\frac{1}{3}=12\]
\[(3x-2)^{\frac{1}{3}}=12/4\]
\[(3x-2)^\frac{1}{3}=3\]
\[[(3x-2)^\frac{1}{3}]^3=3^3\]
\[(3x-2)^{(3)(\frac{1}{3})}=27\]
\[(3x-2)^1=27\]
\[x=(27+2)/3=29/3\]

Answer 19

where r u getting the extra 3