Question

There are 3 red marbles, 4 white marbles, and 1 green marble in a bag. Marbles are drawn without replacement. What is the probability that 3 marbles can be drawn without drawing the green marble?

Answer 1

0.670

Answer 2

ok interesting, how did you get that? can you show me just a little

Answer 3

yep

Answer 4

because there are 8 total marbles, which means that 7 out of the 8 marbles in the bag are not green. So, the probability of not drawing a green marble is 7/8. To draw 3 marbles that aren't green, you multiply 7/8 * 7/8 * 7/8 , which will = .670. Did that help?

Answer 5

the sampling is without replacement

Answer 6

not with replacement

Answer 7

what is the difference involving my question

Answer 8

what do u mean?

Answer 9

it makes the answer not .670

Answer 10

i dont get how it cn be drawn without placement

Answer 11

if the sampling was with replacement then the answer would be .670


but it is not with replacement

Answer 12

ok i understand what your saying, then how do you work this without placement? it cant be that different, can it?

Answer 13

it's not that different

Answer 14

you still have 7/8 for the first draw

for the second draw there is one fewer marble so the probability of not green is 6/7


and then 5/6 for the third


multiply together

Answer 15

ok so 0.625

Answer 16

yes

Answer 17

alright cool, thakn for the help you two

Answer 18

Welcome i tried... XD

Answer 19

i know np