Question

MEDALS FORSURRREEE HELP
\\\\\\\\\///////////////

Answer 1

Do youhave graph paper?

Answer 2

nope....

Answer 3

Know the mid-point formula?

Answer 4

Nope i do not.

Answer 5

The co-ordinates of midpoint(x,y) on the line segment with end-points (x1,y1) and (x2,y2) is just the average of co-ordinates, given by :
\(\large x=\frac{x_1+x_2}{2}\)
\(\large y=\frac{y_1+y_2}{2}\)

Answer 6

Hint: E is the mid-point of A and B.
so with the given formula, can you try to find point E ?

Answer 7

do i need to substitute?

Answer 8

yes,
x1, y1 = -3,-1
x2,y2 = 6,-3

Answer 9

g is 0,-3 because the lines cordinate to numbers f is i think -2.5,4 or 4,-2.5 cordinating to thedashes/lines on the triangle

Answer 10

so? what did you get the co-ordinates of E as?

Answer 11

Hold on hahhaaa.

Answer 12

is it (0,-2.5)? @hartnn

Answer 13

how did you get that?
and NO

Answer 14

i substituted the x1 y1 and x2 y2 INTO THE EQUATION...

Answer 15

x = (-6+3)/2 = ..
y = (-1 + (-3))/2 = ..

Answer 16

(1.5,1)?

Answer 17

6-3 = 3
so,
x = 3/2

-1-3 = -4

so
y = -2

E = (3/2 , -2)

Answer 18

now F,
it is the mid-point of E and B

so now
x1,y1 = 3/2, -2
x2,y2 = 6,-3

use the same formula!

Answer 19

okay hahaa lemme try again

Answer 20

Okay so im obviously doing something wrong, I got (3.75,-2.5)

Answer 21

6+3/2 = 15/2

so
x = 15/4


-2-3 = -5
so y = -5/2

F = -5,-5/2

Answer 22

oops,
F = 15/4, -5/2

Answer 23

Okay so what now?

Answer 24

you already got E and F
thats what you wanted

Answer 25

it was f and g that i neeeded rofl.

Answer 26

means you still need point G

Answer 27

yeahhh.

Answer 28

G divides segment CB internally in the ratio 1:3
(1 parts to 3 parts)

Answer 29

so we use the internal division formula.

\(x = \dfrac{m_1x_1 +m_2x_2 }{m_1+m_2}\)

\(y = \dfrac{m_1y_1 +m_2y_2 }{m_1+m_2}\)

Answer 30

I dont understand that alll. whats m mean?

Answer 31

here,
m1 = 1, m2 = 3
x1, y1 = -3,-3
x2,y2 = 6,-3