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Mathematics 18 Online
OpenStudy (howard-wolowitz):

M&M probanility question in comments

OpenStudy (howard-wolowitz):

OpenStudy (howard-wolowitz):

I think the answer is 0.6

OpenStudy (solomonzelman):

I don't think so.

OpenStudy (anonymous):

0.2

OpenStudy (solomonzelman):

Note that your relative frequencies must add up to 1. Agree?

OpenStudy (howard-wolowitz):

P(R and R) = 0.3^2 P(Y and Y) = 0.1^2 P(G and G) = 0.1^2 P(O and O) = 0.1^2 P(B and B) = 0.1^2

OpenStudy (solomonzelman):

??

OpenStudy (anonymous):

sum up the numbers and divide it by 6 leave your answer in tenth

OpenStudy (solomonzelman):

Your relative frequencies add up to 1. (If you want to know why, ask me....) So, \(\color{#000000}{ \displaystyle 0.3+0.3+x+0.1+0.1 +0.1=1 }\) \(\color{#000000}{ \displaystyle 0.9+x=1 }\) \(\color{#000000}{ \displaystyle x=0.1 }\) So the relative frequency of getting green is 0.1.

OpenStudy (solomonzelman):

What is the probability that you get either blue green or red? (Note that any of them is a desired outcome, so you are fine with (0.3+0.1+0.1) out of 1 (or, out of all possible outcomes). So, \(\color{#000000}{ \displaystyle P({\rm Blue,~Green,~or~Red}) =0.5/1=0.5 }\)

OpenStudy (howard-wolowitz):

wow, you just proved its 0.5

OpenStudy (solomonzelman):

yes, but you said 0.6

OpenStudy (howard-wolowitz):

yea, but i was wrong

OpenStudy (solomonzelman):

with 0.6 or 0.5 ?

OpenStudy (howard-wolowitz):

i said it was 0.6 and thats wrong ,,,, the correct answer is 0.5

OpenStudy (solomonzelman):

yeah, we all make mistakes. It's fine.... now you know, tho'. Good luck with stats:)

OpenStudy (howard-wolowitz):

yes, and thank you

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