M&M probanility question in comments
I think the answer is 0.6
I don't think so.
0.2
Note that your relative frequencies must add up to 1. Agree?
P(R and R) = 0.3^2 P(Y and Y) = 0.1^2 P(G and G) = 0.1^2 P(O and O) = 0.1^2 P(B and B) = 0.1^2
??
sum up the numbers and divide it by 6 leave your answer in tenth
Your relative frequencies add up to 1. (If you want to know why, ask me....) So, \(\color{#000000}{ \displaystyle 0.3+0.3+x+0.1+0.1 +0.1=1 }\) \(\color{#000000}{ \displaystyle 0.9+x=1 }\) \(\color{#000000}{ \displaystyle x=0.1 }\) So the relative frequency of getting green is 0.1.
What is the probability that you get either blue green or red? (Note that any of them is a desired outcome, so you are fine with (0.3+0.1+0.1) out of 1 (or, out of all possible outcomes). So, \(\color{#000000}{ \displaystyle P({\rm Blue,~Green,~or~Red}) =0.5/1=0.5 }\)
wow, you just proved its 0.5
yes, but you said 0.6
yea, but i was wrong
with 0.6 or 0.5 ?
i said it was 0.6 and thats wrong ,,,, the correct answer is 0.5
yeah, we all make mistakes. It's fine.... now you know, tho'. Good luck with stats:)
yes, and thank you
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