Question

The vertex of this parabola is at (5, 5). When the x-value is 6, the
y-value is -1. What is the coefficient of the squared expression in the parabola's equation?

Answer 1

@mathmale this question is a little different

Answer 2

@rebeccaxhawaii

Answer 3

@Directrix

Answer 4

Vertex Form of Parabola

y = a*(x -h)² + k where (h,k) is the vertex

Vertex is (5,5)


y = a*(x -h)² + k

becomes


y = a*(x -5)² + 5

The task is to find a.

Answer 5

how do u find a

Answer 6

how do we solve it

Answer 7

-1 = a*(6 -5)² + 5

-1 = a* (1) ² + 5

Answer 8

whats next

Answer 9

im confused how did we get -6?

Answer 10

(6,-1) is a point on the parabola.

That means: -1 = a*(6 -5)² + 5 We have to solve that for a.

-1 = a*(6 -5)² + 5

-1 = a* (1) ² + 5

-6 = a

Answer 11

The question asks for the coefficient value of the squared term.

y = a*(x -h)² + k

a is the coefficient of the squared term.

a = -6 as we computed.

Answer 12

can we do a different one?

Answer 13

Why do we need to do a different one?

Answer 14

Post a new problem in a new thread.