Question

HELP!!!

Answer 1

How about writing out the formulas for the volume of the cone and the volume of the "sphere" of ice cream? Is the question clear to you? If not, explain.

Answer 2

i know the volume was 1/3pi i think @mathmale

Answer 3

(1/3) and pi are part of the volume formula for the cone, but do not constitute all of the formula. Better look up "volume of a cone." Write this formula down for future reference. What is the formula for the volume of a sphere? Look up "volume of sphere."

Answer 4

ok I found it its V=4/3πr3

Answer 5

that's the formula for what? Note that you'll need to enclose the fraction 4/3 within parentheses to eliminate any possibility of misinterpreting it. Which other formula will you need here?

"Better look up "volume of a cone." Write this formula down for future reference. What is the formula for the volume of a sphere? Look up "volume of sphere."

Answer 6

V=πr2 h/3

Answer 7

@mathmale

Answer 8

Please accept a little editing:

V=πr2 h/3 should actually be written as \[V _{cone}=\frac{ 1 }{ 3 }r^2 h\]

Answer 9

thx

Answer 10

...and the formula for the volume of a sphere is \[V _{sphere}=\frac{ 4 }{ 3 }\pi r^3\]

Answer 11

ok so how would i solve this

Answer 12

So, now, reread the problem statement. What is it asking you to do? Suppose you go to the Del Mar Fair near San Diego on a hot day, and order an ice cream cone exactly as described in this problem statement. Would you presume that the ice cream will exactly fill the cone as it melts, or not quite fill the cone, or fill the cone to overflowing?

Answer 13

What is the radius of the cone's "base?" What is the radius of the sphere? What is the height of the cone?

You now have the 2 volume formulas, one for the cone, one for the sphere. I'd suggest you calculate the volume of each separately and then compare the two volumes.

Answer 14

diameter is 2.5

Answer 15

the cone is 4.75 in

Answer 16

diameter is the same for the cone and uce cream
the radius is 1.25

Answer 17

ok so the first part is volume of the ice cream would i divide the whole thing in half because its half a circle

Answer 18

I'm sure you've ordered an ice cream cone before. Does the server cut the sphere of ice cream in half? No? I thought not. So, no, do not "divide the whole thing in half."

Answer 19

Using the given radius, find the volume of the sphere. Leave pi as pi, rather than approximating it with 3.14 or 22/7.

Answer 20

i know but if you read the question it says 1. As Tiffany scooped ice cream into a cone, she began to formulate a geometry problem in her mind. If the ice cream was perfectly spherical with a diameter of 2.5 inches and sat on a geometric cone that also had a diameter of 2.5 inches and was 4.75 inches tall, would the cone hold all the ice cream as it melted (without her eating any of it)? Find the solution to Tiffany’s problem and justify your answer mathematically.

Answer 21

Sure. what makes y ou think I haven't read the question at least twice?

Answer 22

ok i trust what your saying. lets keep going

Answer 23

The server gives you this perfect ice cream cone, and somehow you resist eating any of it. What happens to the ice cream on a warm day?

Answer 24

ice cream melts

Answer 25

Where does the melted ice cream go?

Answer 26

You're still not allowed to even taste it. ;(

Answer 27

in the cone

Answer 28

lol

Answer 29

Yes. will the melted ice cream completely fill the cone, but not run over? Or will it run over? Or won't there be enuf to fill the entire cone? How are you going to answer these questions?

Answer 30

ok i am solving for the volume of the ice cream tell me if its right

Answer 31

I'l make a deal with you: I'll tell you whether or not it's right if you show every step of the work you do.

Answer 32

deal

Answer 33

Lol. I believe in your skittles.

Answer 34

So, according to your calculations, the volume of the spherical scoop of ice cream is .. ?

Answer 35

Except in your case, skittles are not better than chocolate mocha ice cream.

Answer 36

skittles?

Answer 37

\[V=\frac{ 4 }{ 3}πr3 \]
\[V=\frac{ 4 }{ 3}π(1.25)3 \]
\[V=\frac{ 4 }{ 3}\left( 1.25 \right)^{3}=2.06\]
\[V=1.67π^{3}=2.4\]

Answer 38

@mathmale is it correct

Answer 39

I'm skipping the 2nd of your four equations, because of the 3 being in the wrong place. The third equation shows the exponent, 3, in the correct place.

Answer 40

Where did the 2.06 come from?

Answer 41

I get a considerably different result from yours for the volume of the sphere.

V is (4/3) pi (radius)^2

Answer 42

Type that again, this time subst. r=1.25 inches

Answer 43

sorry little error
\[V=\frac{ 4 }{ 3 }\left( 1.25 \right)=2.06\]

Answer 44

It isn't radius^2, its radius^3...
Well according to google.

Answer 45

it is a 3

Answer 46

\[V=\frac{ 4 }{ 3}πr3: No\]

Answer 47

\[V=\frac{ 4 }{ 3}πr^3:~Yes\]

Answer 48

wait look at the next step

Answer 49

Skittles, where did you get 2.06 from. I'm so confused o.O

Answer 50

i just wrote it its 4/3 x 1.25

Answer 51

Well anyways, I got a complete different answer than you. Hint: If there is no variable, you shouldn't have to make the equation equal to something. You should just plug in the radius which is 1.25, and plug in pi (which is either 3.14 or actually putting the pi sign) and multiply straight forwards. Just remember to use PEMDAS first so do the exponents.

Answer 52

\[V=\frac{ 4 }{ 3}πr^3~becomes~V=\frac{ 4 }{ 3}π(1.25 ~inches)^3\]

Answer 53

ok

Answer 54

Order of operations rules require that you do the exponentiation first: in other words, you must evaluate (1.25 inches)^3 first.

Answer 55

\[V=\frac{ 4 }{ 3}π(1.25~ inches)^3~becomes ~what?\]

Answer 56

8.18

Answer 57

Yay! Good Job.

Answer 58

:)

Answer 59

Great. Now, using some of the tricks I've shared with you, please find the volume of the hollow, conical, sugary ice cream cone.

Answer 60

Oh right... you're only half done xD.

Answer 61

ok

Answer 62

Great. Now, using some of the tricks I've shared with you, please find the volume of the hollow, conical, sugary ice cream cone.

Answer 63

2.47

Answer 64

Remember our deal? You've got to show how you've obtained your results.

Answer 65

xD

Answer 66

\[V _{cone}=\frac{ 1 }{ 3 } \pi r^2 h\]

Answer 67

You have 2 variables here: r and h. You must substitute the given values for r and h into this formula.

Answer 68

gonna show your work?