How do I eliminate the parameter t for x=cos(t)-sin(t), y=cos(t)+sin(t)?
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OpenStudy (freckles):
have you tried to see what x^2+y^2 gives you ?
OpenStudy (anonymous):
yes it gives cos^2(t)-2cos(t)sin(t)+sin^2(t)+cos^2(t)+2cos(t)sin(t)+sin^2(t)
which gives 2cos^2(t)+2sin^2(t)
OpenStudy (freckles):
what is cos^2(t)+sin^2(t)=?
OpenStudy (freckles):
thinking Pythagorean identity
OpenStudy (anonymous):
I got x^2+y^2 is 2
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OpenStudy (freckles):
cool stuff
OpenStudy (freckles):
you have eliminated the variable t
OpenStudy (anonymous):
yes, i see
OpenStudy (anonymous):
how do i graph the parametric equation?
I'm getting a nonsense plot points
OpenStudy (freckles):
have you ever graph circles in the past?
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OpenStudy (anonymous):
not really
OpenStudy (freckles):
\[d=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}\]
this is the distance between (x1,y1) and (x2,y2)
do you know this?
OpenStudy (anonymous):
yes
OpenStudy (freckles):
|dw:1458873236372:dw|
say I drew a perfect circle here
and we have that any line segment that I draw from the center to a point on the circle are of equal distance
OpenStudy (freckles):
it is called a radius by the way
let's say the distance between (h,k) and call that point on the circle I just drew (x,y) |dw:1458873327809:dw|