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Mathematics 6 Online
OpenStudy (anonymous):

How do I eliminate the parameter t for x=cos(t)-sin(t), y=cos(t)+sin(t)?

OpenStudy (freckles):

have you tried to see what x^2+y^2 gives you ?

OpenStudy (anonymous):

yes it gives cos^2(t)-2cos(t)sin(t)+sin^2(t)+cos^2(t)+2cos(t)sin(t)+sin^2(t) which gives 2cos^2(t)+2sin^2(t)

OpenStudy (freckles):

what is cos^2(t)+sin^2(t)=?

OpenStudy (freckles):

thinking Pythagorean identity

OpenStudy (anonymous):

I got x^2+y^2 is 2

OpenStudy (freckles):

cool stuff

OpenStudy (freckles):

you have eliminated the variable t

OpenStudy (anonymous):

yes, i see

OpenStudy (anonymous):

how do i graph the parametric equation? I'm getting a nonsense plot points

OpenStudy (freckles):

have you ever graph circles in the past?

OpenStudy (anonymous):

not really

OpenStudy (freckles):

\[d=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}\] this is the distance between (x1,y1) and (x2,y2) do you know this?

OpenStudy (anonymous):

yes

OpenStudy (freckles):

|dw:1458873236372:dw| say I drew a perfect circle here and we have that any line segment that I draw from the center to a point on the circle are of equal distance

OpenStudy (freckles):

it is called a radius by the way let's say the distance between (h,k) and call that point on the circle I just drew (x,y) |dw:1458873327809:dw|

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