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The value of lim e^xcosx-1-x/sin(x^2) where x----->0 is equal to..
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My ans is 0..
@hartnn
And 1/2 also...how is it possible??
I did it by two methods resulting in two diff ans ..
First of all i multiplied e^xcosx-1 by xcosx and divided it by same.. Then i got xcosx-x/x^2 Solving this limit i got 0..
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you have used lim x->0 (e^x-1)/x =1 in the numerator...but is that legal step ? lim (ab+c)/d does not equal lim [(lim a)b+c]/d
Can't we write like this Lim (e^xcosx -1 -x ) = lim (e^xcosx-1)- limx
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