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@FFASinger
Hint: You have to change all the bases to the same base. Ex. change all to base 4. Another hint: 1/ 64 = 64^-1
Since they are the same base, then you can use exponenet laws and add exponenets
you could plug in each option and see which fits , if any
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on the right side
Put the value of s=-1 on left side of equation.
yes 16^(2s+ 2) = 4^2(2s + 2) = 4^(4s + 4)
so 1/64 = 4^-3 = 4^(2s-1) * 4^(4s + 4) -3 = 2s - 1+ 4s + 4 solve for s
it would be -1 correct
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the value of s shows wheter it has solution or not. In this situation, you have to add and substract the like terms. The solve for s. See what you get.
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