I'm not clear how to 'complete the square' with the equation x=y^2. Help? I need to do this to find the directrix and focus. Clearly the vertex is (0,0) but that is all I can figure out. Thanks! :D
Hello, Cecil-Weasel. Pop goes the weasel. "I'm not clear how to 'complete the square' with the equation x=y^2" Cecil, you don't need to complete the square here, since y^2 is in itself a perfect square. I take it you are to find the vertex, the focus and the directrix. Have you found these before, in other problems?
Yes, it takes me a while but I can usually get it. I think the trouble here is that the equation is not set up as x=ay^2+by+c. Instead it is missing a b(y). I feel that it should be easier but I'm not sure where to start.
I'll drop you some hints. This is a horizontal parabola; it opens to the right. Let p be the positive distance from the vertex to the focus in such a horiz. parab. The general equation for such a parab. is 4px=y^2. Reference: http://colalg.math.csusb.edu/~devel/precalcdemo/conics/src/parabola.html Suppose y=1. What would x be? Start with x=y^2.
@Cecil_the_Weasel ? Awaiting your response.
Hmm... I'm still having trouble setting up the problem. @mathmale
You were given x=y^2. You've correctly figured that the vertex is at (0,0). Suppose I arbitrarily gave you y=1. What would x be in this case?
Also 1
Correct. Now, another form of the equation for this horiz. parab. is 4px=y^2. Start with the coordinates of the point (1,1). Subs. x=1 and y=1 into the above eq'n. calculate p.
p= 1/4
Oh! So would that be the focus? (If I switched the x and y again to make it horizontal) @mathmale
p=1/4 is not so much the focus as it is the distance from vertex to focus. p is also the distance from vertex to directrix. What is the eq'n of the directrix for this horiz. parab.?
x=-.25?
Yes, or x=-1/4. Very good!
Focus?
The value p in this situation would be the value of the focus in this particular problem because the focus is zero. I see now. Thank you very much :D
*the orgin is zero whoops
silly me
Actually, p represents a distance; the focus is written as (1/4, 0). No, not silly you. ;)
Thanks again :D I won't fail my test haha!
Hope not! Come back another time. Bye!
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