Question

Please help ASP Will medal questions are below

Answer 1

1) add. simplfiy by collecting like radical terms if possible \[6\sqrt{72}+9\sqrt{18}\]

Answer 2

2) Multiply and simplify by factoring \[\sqrt{14}\times \sqrt{6}\]

Answer 3

3) Simplfiy by factoring . Assume that all expression under radicals represent nonnegative numbers \[\sqrt{49m}^{15}\]

Answer 4

@Ms-Brains

Answer 5

What do you think..?

Answer 6

I don't know I'm not really good with square roots

Answer 7

@ILovePuppiesLol would you please help me

Answer 8

i have no clue lol, I'm bad at math remember, but i do have a good friend who is excellent at math! @mathmale

Answer 9

Okay thanks anyways

Answer 10

@mathmale can you help me please?

Answer 11

Hello!

Simplify: \[6\sqrt{72}+9\sqrt{18}\]

Answer 12

the trick here is to identify the LARGEST perfect square factors of 72 and 18 under their respective radical signs.

Perfect squares consist of 1, 4, 9, 16, 25, 36, and so on.

Which of these is the largest that would divide into 72 with no remainder?
into 18 with no remainder?

Answer 13

\[72\div9=8\]
and\[18\div9=2\]

Answer 14

So, it surely appears that 9 is the largest perfect square factor of both 72 and 18.

Answer 15

Thus, your\[6\sqrt{72}+9\sqrt{18}\]...

becomes \[6\sqrt{8*9}+9\sqrt{2*9}\]

Answer 16

Can you separate \[\sqrt{8*9} \] ... into two factors?

Answer 17

\[\sqrt{?}\sqrt{?}\]

Answer 18

like this?
\[2\times4=8\]
and
\[3\times3=9\]

Answer 19

Good start. \[\sqrt{8}\sqrt{9}=?\]

Answer 20

\[\sqrt{72}\]

Answer 21

\[\sqrt{9}*\sqrt{2}=?\]

Answer 22

\[\sqrt{18}\]

Answer 23

Remember, we're trying to simplify, not to work back to our original expression.
We started with sqrt(72) and obtained sqrt(8)*sqrt(9).
Try to simplify; don't multiply here.

Answer 24

so if we're trying to simllify would we do something like this?\[6\sqrt{72}+9\sqrt{18}=6\sqrt{36}\times2+9\sqrt{9}\times2\]
which would equal \[6\sqrt{36}\sqrt{2}+9\sqrt{9}\sqrt{2}\]

Answer 25

then rewrite it\[6\times6\sqrt{2}+9\times3\sqrt{2}\]
Multiply \[36\sqrt{2}+27\sqrt{2}\]

Answer 26

then we would use the distributive property to combine like radicals
\[(36+27)\sqrt{2}\]

Answer 27

That surely looks good, and I appreciate your sharing your work.

Answer 28

Add\[63\sqrt{2}\]
would be the answer right?

Answer 29

\[6\sqrt{8*9}+9\sqrt{2*9}\]

Answer 30

becomes\[18\sqrt{8}+27\sqrt{2}\]

Answer 31

Yes, looks like you're ab solutely on track. Nice work!

Answer 32

Thanks Mathmale

Answer 33

My pleasure! Keep up the good work.