Question

Solve the equation 2x^3 - x^2 - 8x + 4 = 0 algebraically for all the values of x

Answer 1

@Kainui

Answer 2

Try factoring by grouping to get at least one root.

2x^3 - x^2 - 8x + 4 = 0 =

x^2 ( 2x - 1) - 4 ( 2x - 1) =

Answer 3

Okay. And then?

Answer 4

x^2 ( 2x - 1) - 4 ( 2x - 1) =

The common factor is (2x - 1)

Answer 5

ok

Answer 6

x^2 ( 2x - 1) - 4 ( 2x - 1) =

( 2x - 1) ( x^2 - 4)

Answer 7

( 2x - 1) ( x^2 - 4) - 0

Use the Zero Product Property to solve for x.

Note that x^2 - 4 is the difference of 2 squares.

Answer 8

ok gimme a moment

Answer 9

Alrighty.
Take your time.

"Fast is fine, but accuracy is everything." ~Wyatt Earp

Answer 10

so i have
(x+2)(x-2)(2x-1)
x = -2, 2, 0

Answer 11

How did you get 0 for this: (2x-1)= 0

Answer 12

oh sorry. i meant 1/2

Answer 13

1/2, 2, and -2 Correct.

Answer 14

i have other questions can i post them for help?

Answer 15

and thanks for ur help

Answer 16

Yes. Start a new thread, okay?

Answer 17

ok

Answer 18

You are welcome.