Question

Someone help me please, I'll fan, medal, and help you in any other subject.

Answer 1

@FaiqRaees

Answer 2

So this one's opposite adjacent so I need to find sin-1?

Answer 3

2 is base and 5 is perpendicular

Answer 4

Oh, Then can you help me, I'm not sure about it

Answer 5

do you know what is base and perpendicular

Answer 6

I think it's something with hypotenuse... Hold on, let me check.

Answer 7

Both the "adjacent side" and the "opposite side" of angle B are given. Which trig function of B involves both the adjacent and opposite sides? No, it's not the sine.

Answer 8

Adjacent/ hypotenuse.
using arcctan?

Answer 9

You want to determine Angle B, not the hypotenuse length.

Answer 10

Why include "hypotenuse?" How is that needed here?

Answer 11

..... I'm so confused now.

Answer 12

Ask some questions to help yourself reduce your confusion.

You mention sine ... why?

Before you choose one of the basic trig functions to apply here,
list their names and their definitions.

Answer 13

Because don't I have to find the sine of 5/2 then the Arctan, arccos?

Answer 14

I thought I had to find cos-1 first, then the arctan, then arccos

Answer 15

There's more than one way to skin a cat, and more than one way to solve this problem.
You are given the lengths of the adjacent and opposite sides, so my question for you is "Why do you need to consider the hypotenuse at all?"

Which trig function or functions mention(s) the opp. side and the adj. side, but NOT the hyp?

Answer 16

the cosine function involves the hypotenuse, so there's no point in using that function unless you want to go thru the (unnecessary) trouble of finding the length of the hyp.

Answer 17

You're not really helping me at all by not telling me the formulas I'm asking... If I knew which one it was I could solve it..

Answer 18

You MUST know the definitions of the sine, cosine and tangent functions. If you're not willing to look those up as I've asked, then perhaps we should terminate this conversation.

If you choose to continue, type out the definitions of the sine, cosine and tangent functions as I have asked you several times to do.

Answer 19

Khan Academy is bad :/

Answer 20

I'll find someone else to help me considering I know what all of those are, but, have no idea which steps to use on this triangle because, on person told me one thing, and someone else told me another. Instead of being rude to people, and expecting them to know everything you should explain things to them, and help step them through until they get it, the whole point of open study is to help people, not be rude and expect them to know everything. They came here for help... @mathmale

Answer 21

@Seratul I know, it really is, you get one thing wrong, and It restarts you, and none of their videos are helpful.

Answer 22

I have my doubts regarding your knowledge of the basic trig functions, the sine, cosine and tangent, since in more than twenty minutes, I have not succeeded in getting you to demonstrate that you actually know them, by typing them out. Have you ever considered that it might actually help you to cooperate with someone trying to help you?

I'm sorry you don't like my style and are not willing to answer the questions I am asking you to guide you towards a solution of this problem.

Good luck. I'm signing off.

Answer 23

All @mathmale is telling you to do is write out the formulas for sine, cosine, and tangent. Since I know mathmale is going to help you out a lot, I will write out the formulas for purpose of education

Sine= Opposite/Hypotenuse
Cosine= Adjacent/Hypotenuse
Tangent= Opposite/Adjacent.

Since it is asking you to find an angle, you will have to use an inverse operation. Due to the fact that we are not given the hypotenuse of the triangle, you will have to do the inverse of tangent. Here is what the equation should look like:
\[\sin^{-1} \frac{ 5 }{ 2 }\]
Now just type this in your calculator and you should get your answer.

Answer 24

@Seratul 0.84

Answer 25

Then 84 degrees should be your answer if you did it correctly.

Answer 26

it's not correct

Answer 27

I think you did something wrong. I don't have a calculator on me but I think you didn't change your options.

Answer 28

https://www.google.com/search?espv=2&q=inverse+tan++5%2F2&oq=inverse+tan++5%2F2&gs_l=serp.3..0i30.9461.13675.0.13857.17.16.0.0.0.0.142.1445.9j5.14.0....0...1.1.64.serp..5.10.1064.NTbYiR1ZeyU

Answer 29

Oh, I am very sorry. Instead of putting tan, i told you to put sin even though above I said to use tan xD. This just proves its better to do step by step and not just rely on someones answer.

Answer 30

thanks to seratul., we finally have the correct definition for the tangent function:

Tangent of angle x= Opposite/Adjacent.

Your opp. side is 5 and your adj. side is 2.

Thus, Angle B is arctan (5/2), also written as \[\tan ^{-1}\frac{ 5 }{ 2 }=B\]

Answer 31

Set your calculator to either DEGREE or RADIAN mode, whichever y ou preser.

What is your result for Angle B?

Thanks very much, seratul.

Answer 32

B = ? in degrees

B = ? in radians