Question

Simplify: u"e^(x)-2u"xe^(x)-4u'xe^(x)+4u'e^(x)=(1-4x+4x^2)e^x

Answer 1

\[u''e^x-2u''xe^x-4u'xe^x+4u'e^x=(1-4x+4x^2)e^x \]

Answer 2

@freckles @thomaster

Answer 3

u"e^x(1-2x) +4u'e^x(1-x)=(1-4x-4x^2)e^x
Divide both side by e^x
=u"(1-2x) +u'(1-x)= (1-4x-4x^2)

Answer 4

Now multiply both side by dx then integrate it

Answer 5

@mathstudent55