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Mathematics 7 Online
OpenStudy (anonymous):

http://prntscr.com/al82di Can someone assist me with this quick question? It's only one, I will give a medal and I will fan! :)

OpenStudy (michaelbp):

68 i think

OpenStudy (mathmale):

Find the length of the diagonal (from the problem description). How is the length of the diagonal (hypotenuse) related to the length of one side of the square? Now, to find the perimeter. Given the length of one side of a square, how would you find the permeter?

OpenStudy (anonymous):

Thank you, but can you explain so that I know you may be correct?

OpenStudy (anonymous):

@mathmale I don't know what why I find this certain question hard.

OpenStudy (mathmale):

Are you familiar with the pythagorean Theorem?

OpenStudy (anonymous):

The only thing I know how to do is A^2+b^2=c^2 Could you explain why the answer would be 68?

OpenStudy (mathmale):

Your first unknown quantity is the length of ONE side of the square. Call that length " x ." |dw:1459191817906:dw|

OpenStudy (mathmale):

We'll get to the 68. First things first. Can you now apply the Pyth Them to the triangle in this illustration? Hyp=34 ft side 1 x side 2 x

OpenStudy (mathmale):

Remember: The Pyth. Thm. requires that you square all three of these lengths.

OpenStudy (anonymous):

Oh wait, I just received help from another website that showed me how to do it, I had to come to open study because they werent responding, but thanks you! The answer is 68.

OpenStudy (mathmale):

Happy you're happy. Take care.

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