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OpenStudy (anonymous):
please help with statistics question! http://prntscr.com/alcegq
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jimthompson5910 (jim_thompson5910):
do the formulas given in the hints look familiar and make sense?
OpenStudy (anonymous):
not to me they don't, i have been trying it out but get nowhere
jimthompson5910 (jim_thompson5910):
do you agree that the highest score is 25? I'm referring to the dot plot
OpenStudy (anonymous):
yes
jimthompson5910 (jim_thompson5910):
what is the lowest value on that same dotplot?
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OpenStudy (anonymous):
-18 ?
jimthompson5910 (jim_thompson5910):
yes
So XH = 25 and XL = -18
subtracting the two values
XH - XL = ???
OpenStudy (anonymous):
43
OpenStudy (anonymous):
divided by 6 = 1.16
jimthompson5910 (jim_thompson5910):
now divide that by 6 to compute the SD
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OpenStudy (anonymous):
ooops 7.16
jimthompson5910 (jim_thompson5910):
7.16666666666667 roughly
jimthompson5910 (jim_thompson5910):
now you'll use this SD value to plug into the ME formula
ME = margin of error
jimthompson5910 (jim_thompson5910):
\[\Large ME = \pm 2 \times \frac{SD}{\sqrt{N}}\]
\[\Large ME \approx \pm 2 \times \frac{7.16666666666667}{\sqrt{50}}\]
\[\Large ME \approx ??\]
OpenStudy (anonymous):
okay
I got 2.02704
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jimthompson5910 (jim_thompson5910):
which rounds to 2.03
OpenStudy (anonymous):
great! thank you!
jimthompson5910 (jim_thompson5910):
so the margin of error (ME) is roughly +-2.03
OpenStudy (anonymous):
perfect
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