Mathematics
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OpenStudy (kayders1997):
Find the integral of x(2x+5)^8dx
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OpenStudy (kayders1997):
@satellite73
OpenStudy (kayders1997):
@ganeshie8
OpenStudy (vishweshshrimali5):
\(\int x(2x+5)^8 dx\)
Put, 2x + 5 = u
OpenStudy (vishweshshrimali5):
What will be x and dx in terms of u ?
OpenStudy (kayders1997):
Du=2dx
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OpenStudy (kayders1997):
I don't know if that's right though because you need to get back to xdx
OpenStudy (anonymous):
you can use \[u=2x+5\]then solve the equation for \(x\) in terms of \(yu\)
OpenStudy (anonymous):
i meant solve for \(x\) in terms of \(u\)
OpenStudy (vishweshshrimali5):
du = 2dx is correct
What about x in terms of u ?
OpenStudy (kayders1997):
But wouldn't that be du=2dx is there something I could do different?
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OpenStudy (kayders1997):
Okay
OpenStudy (anonymous):
it is kind of going to suck, but you can do it
OpenStudy (vishweshshrimali5):
Yeps :P
OpenStudy (anonymous):
\[x=\frac{u-5}{2}\]
OpenStudy (kayders1997):
I've never done a problem like this
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OpenStudy (anonymous):
maybe it is a typo
OpenStudy (kayders1997):
It's out of a calculus book
OpenStudy (vishweshshrimali5):
No problem then.. Your integral will become:
\cfrac{1}{2}\[\int \cfrac{u - 5}{2}u^5 du\]
OpenStudy (anonymous):
ok then grind it till you find it
btw calc books have typos too
lots of them
OpenStudy (kayders1997):
Why u^5? Hmmmm
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OpenStudy (vishweshshrimali5):
Sorry the integral is:
\[\cfrac{1}{2}\int \cfrac{u - 5}{2}u^8 du\]
\[=\cfrac{1}{4} \int (u^9 - 5u^8) du\]
OpenStudy (vishweshshrimali5):
Can you solve this?
OpenStudy (kayders1997):
Yeah just a second I'm processing the information you just gave
OpenStudy (vishweshshrimali5):
Sure
OpenStudy (kayders1997):
The one thing I don't understand us why 1/2 is in front of the integral?
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OpenStudy (vishweshshrimali5):
Recall that we got du = 2dx
=> dx = du/2
So, this is where we got that that 1/2
OpenStudy (kayders1997):
Oh okay!
OpenStudy (kayders1997):
I got 1/40(2x+5)^10-5/36(2x+5)^9
OpenStudy (kayders1997):
Sorry if that's hard to read
OpenStudy (vishweshshrimali5):
Perfect!! Don't forget the integration constant C
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OpenStudy (kayders1997):
I always forget it!!!! Ugh!!!!
OpenStudy (vishweshshrimali5):
:) It's alright!
OpenStudy (kayders1997):
Thank you so much :)
OpenStudy (vishweshshrimali5):
Glad to be of help :)
OpenStudy (kayders1997):
Definitely a fan
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OpenStudy (kayders1997):
Would you be able to help with a different topic soon?
OpenStudy (kayders1997):
I'm not good at intragration by parts