Question

Will Give Medal!!!


The distance traveled, in meters, of a coin dropped from a tall building is modeled by the equation d(t) = 4.9t2 where d equals the distance traveled at time t seconds and t equals the time in seconds. What does the average rate of change of d(t) from t = 3 to t = 6 represent?

Answer 1

The coin travels an average distance of 44.1 meters from 3 seconds to 6 seconds.
The coin falls down with an average speed of 14.7 meters per second from 3 seconds to 6 seconds.
The coin falls down with an average speed of 44.1 meters per second from 3 seconds to 6 seconds.
The coin travels an average distance of 14.7 meters from 3 seconds to 6 seconds.

Answer 2

what is \(d(3)\)?

Answer 3

216.09... @satellite73

Answer 4

skip that i mean what about \(d(6)\)?

Answer 5

IfI am doing it right then 864.36 @satellite73

Answer 6

ok now subtract those two

Answer 7

ok i would get 648.27

Answer 8

hold on a sec, something might be wrong

Answer 9

ok

Answer 10

http://www.wolframalpha.com/input/?i=4.9*6^2

Answer 11

http://www.wolframalpha.com/input/?i=4.9*3^2

Answer 12

http://www.wolframalpha.com/input/?i=4.9*6^2-4.9*3^2

Answer 13

i got different number than you

Answer 14

Oh ok i had put the 3 and 6 in wrong my bad
so is the differenc eof those two 132.3??

Answer 15

yes, now divide by 3

Answer 16

44.1

Answer 17

So would it be option one or 3...? @satellite73

Answer 18

yes 44.1 is the average distance over time

Answer 19

So option 1..?

Answer 20

distance divided by time is rate (speed)

Answer 21

Of so option3...

Answer 22

3
distance is 132.3
times is 6-3 = 3
distance divided by time is rate

Answer 23

oh ok thank you :)

Answer 24

yw