Question

1.Solve the system of equations algebraically.Show all your steps.
y=x^2+2x
y=3x+20

Answer 1

x^2+2x=3x+20 is a quadratic equation

write in standard form ax^2+bx+c=0
you can try to factor ax^2+bx+c
or just use quadratic formula

Answer 2

there is also completing the square if you wish
we just put it in the form x^2+bx=k
and add (b/2)^2 on both sides
giving x^2+bx+(b/2)^2=k+(b/2)^2
then this let's us write that one side as a square
(x+b/2)^2=k+(b/2)^2
then so on...

Answer 3

okay thank you @freckles do you think you can lead me threw if by telling me to plug them all in and tell me if I got it right or not and help a little bit more. I don't know how to solve this correctly so I want to make sure I get it right when I do

Answer 4

ok please let me know what you after putting it in standard form

Answer 5

like what would be the first step in moving everything to one side?

Answer 6

you have two steps to perform to do do this

Answer 7

either one can go first

Answer 8

are you still there?

Answer 9

ax^2+bx+c=0
is the standard form? and I plug
3x^+20+?=0???

Answer 10

I'm sorry I honestly really don't have no idea how to solve or do thi . This why I need help learning how

Answer 11

\[x^2+2x=3x+20 \]
we are trying to get everything to one side
your first could have been to subtract 3x on both sides
\[x^2+2x \color{red}{-3x}=3x+20\color{red}{-3x}\]
redordering so like terms are together:
\[x^2+2x-3x=3x-3x+20\]
\[x^2-x=0+20\]
\[x^2-x=20\]
You still like one more step to have everything on one side together

Answer 12

What and where is the last step?
Question does that solve one of the equations for the problem or both? I'm kinda confused now

Answer 13

@freckles ....you there???

Answer 14

have you moved everything to one side yet?

Answer 15

there is one more step to do so

Answer 16

do you see that 20 on the side
what do we need to do to both sides so that one side is 0