Question

Graph https://api.agilixbuzz.com/Resz/~Ey6YBAAAAAQniGNz21neSA.41k246z9iiDVClXqgS9LVB/19809088,B84/Assets/assessmentimages/alg%202%20pt%202%20u2l6%203.jpg

Answer 1

https://api.agilixbuzz.com/Resz/~Ey6YBAAAAAQniGNz21neSA.41k246z9iiDVClXqgS9LVB/19809088,B84/Assets/assessmentimages/alg%202%20pt%202%20u2l6%204.jpg
https://api.agilixbuzz.com/Resz/~Ey6YBAAAAAQniGNz21neSA.41k246z9iiDVClXqgS9LVB/19809088,B84/Assets/assessmentimages/alg%202%20pt%202%20u2l6%206.jpg
https://api.agilixbuzz.com/Resz/~Ey6YBAAAAAQniGNz21neSA.41k246z9iiDVClXqgS9LVB/19809088,B84/Assets/assessmentimages/alg%202%20pt%202%20u2l6%205.jpg
none of these

Answer 2

@texaschic101

Answer 3

\left[0,\:2\pi \right]

Answer 4

\[\left[0,\:2\pi \right]\]

Answer 5

?

Answer 6

@ganeshie8

Answer 7

so it is none of the graphs @texaschic101

Answer 8

?

Answer 9

@Directrix

Answer 10

@freckles

Answer 11

is it none of the graphs

Answer 12

I thought that was a - sign and a fraction in front of the cot thing

but it looks like it is just a long fraction bar

so you are looking at
\[y=\frac{\pi}{4} \cot(x-\frac{\pi}{4})\]

we can find the zeros of the graph by solving cos(x-pi/4)=0

and find the vertical asymptotes by solving sin(x-pi/4)=0

Answer 13

ok how would I do that

Answer 14

\[\cos(u)=0 \text{ when } u=\frac{\pi}{2}+n \pi \\ \text{ so } \\ \cos(x-\frac{\pi}{4})= 0\text{ when } x-\frac{\pi}{4}=\frac{\pi}{2}+n \pi \\ x=\frac{3\pi}{4}+n \pi\]
so you have the graph crosses the x-axis at the following x values in the interval given:
-5pi/4,-pi/4,3pi/4, 7pi/4

you can try solving for the vertical asymptotes in a similar way

Answer 15

?

Answer 16

I am so confused

Answer 17

do you know how to solve cos(u)=0?

Answer 18

no

Answer 19

oh then how do you do this problem?

Answer 20

are you just suppose to graph it on your calculator ?

Answer 21

Im not sure and yes and figure out what graph it is

Answer 22

well if you don't need to do any math just use your calculator...

Answer 23

are you sure you aren't suppose to do any math?

Answer 24

I did and I still dont get a graph so can you show me?

Answer 25

well you can play with the window on your calculator options
sometimes the window is what causes the graph not to show up

Answer 26

like what is the window viewing settings set to?

Answer 27

What is that?

Answer 28

the window is from what lower x to what upper x and what lower y and upper y you want to view the graph
like it might by called xmin xmax ymin and ymax

what kind of calculator are you using

Answer 29

I would set
xmin=-6.5
xmax=6.5
since we are looking at (-2pi,2pi)

Answer 30

And I would set
ymin=-10
ymax=10

Answer 31

I know but what graph is it from the above options

Answer 32

can you tell me if your graph you have graphed in your calculator is increasing or decreasing?

Answer 33

like on one cycle

Answer 34

decreasing

Answer 35

but graph A shows a graph that is increasing so can't be graph A

Answer 36

can it by graph B? make some observations ? look at the midpoint of one cycle
is the midpoint a zero?

Answer 37

no?

Answer 38

your midpoint of one cycle lays on the x-axis
while a midpoint of B's graph lays well above the x-axis

Answer 39

what can you say about graph C?

Answer 40

do you notice any difference between graph C and your graph?

Answer 41

that the midpoint is 0?

Answer 42

they both have the midpoint of a cycle being 0 don't they?

Answer 43

I think so?

Answer 44

this what I mean by one cycle