Follow the directions for each problem to write a quadratic equation that has the given number of
solutions. Be sure to show all the work leading to your answer.
Think of another quadratic equation that has two (2) real number solutions. Write the
equation in ax^2 + bx + c = 0 form. Then find the value of the discriminant to support your
answer.

Question

Follow the directions for each problem to write a quadratic equation that has the given number of
solutions. Be sure to show all the work leading to your answer.
Think of another quadratic equation that has two (2) real number solutions. Write the
equation in  ax^2 + bx + c = 0 form. Then find the value of the discriminant to support your
answer.

anonymous · Answer

@4everaddicted2anime

4everaddicted2anime · Answer

Here is a quadratic equation that has 2 solutions:
$$x^2+3x-4=0$$
Do you know how to find the discriminant?

anonymous · Answer

not off the top  of my head

4everaddicted2anime · Answer

Here is the discriminant formula:
$$b^2-4ac$$

anonymous · Answer

ok

4everaddicted2anime · Answer

What are the values for a b and c in the equation I gave you?

anonymous · Answer

= - 4ac + b^2

4everaddicted2anime · Answer

Quadratic equations look like this:
ax^2 + bx + c =0
The equation I gave you is:
x^2 + 3x -4 =0
What is the value of a? b? c?

4everaddicted2anime · Answer

a=1
b=3
c=-4
Now plug that into the discriminant formula

anonymous · Answer

ok 1^2+3x−4=0

4everaddicted2anime · Answer

no. What you should have after plugging these numbers into the iscriminant formula is:
3^2 -4(1)(-4)=?

anonymous · Answer

25

4everaddicted2anime · Answer

Good job. When the discriminant is negative there are no real solutions. When the discriminant equals zero it has one solution. When the discriminant is bigger than zero it has 2 solutions.