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Is Sec x tanx(1-sin^2x) = sinx a Identitie
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Take any value of x and input into both sides of both sides give the same value thennyes it is a identity
Kind of makes sense ?
And yes it is and identity. You can prove it using trignometric identities
Okay Thanks!
Use the identity: \(\sin^2 x + \cos ^2 x = 1~~~ \rightarrow ~~~\cos^2 x = 1 - \sin^2 x\)\) Also, \(\sec x = \dfrac{1}{\cos x}\), and \(\tan x = \dfrac{\sin x}{\cos x} \). \(\sec x \tan x(1 - \sin^2 x) = \sin x\) \(\dfrac{1}{\cos x} \times \dfrac{\sin x}{\cos x} \times \cos^2 x = \sin x\) \(\dfrac{\sin x}{\cos^2 x} \times \cos^2 x = \sin x\) \(\dfrac{\sin x}{\cancel{\cos^2 x}} \times \cancel{\cos^2 x} = \sin x\) \(\sin x = \sin x\)
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It is an identity.
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